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Let

S=1+r+r2+r3+…,|r|<1
  1. By considering

    dSdr

    find a formula for

    1+2r+3r2+4r3+…
  2. Hence, find the value of

    ∑k=1∞k2k−1

For (a), remember that

1+r+r2+…=11−r

Again for (a), you can write this as

1+r+r2+…=(1−r)−1

Differentiating the left side is easy; differentiating the right side needs the chain rule.


For (b), try writing out the first few terms of the sum and think about what value of r in the formula you got from (a) would work this out for you.