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Below is a sketch of

y=1(x−1)(x+2)

Hence, sketch

y=12(2x−1)(x+1)

Let

f(x)=1(x−1)(x+2)

be the original function, which is sketched for us.

Write the new function as

12(2x−1)(x+2)=1(2x−1)(2x+2)

(we have put the 2 into the second bracket).


Based on the hint above, x has been replaced with 2x, so we have to sketch

y=f(2x)

which is an enlargement, scale factor 12, parallel to the x axis.