1. Show that the first derivative of $2^{x^2}$ is

2. Show that the curve

   $$y=2^{x^2}-3x$$

   has a turning point in the region

   $$1<x<1.1$$

3. By choosing a suitable interval, determine, correct to $2$ decimal places, the $x$ coordinate of the turning point.

Differentiating $2^{x^2}$ is a little tricky.

Try this:

Then use implicit differentiation to find $\frac{du}{dx}$.

To locate the turning point, you need to consider

Give your answer to (b) below.