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The solutions of the equation

3(x+1)(x−5)=(x+3)(x+5)

in simplest form are

a±bc

Find the value of abc.

Hint

Expand both sides, collect everything on the left-hand-side.

Solution

We expand and simplify both sides

3(x+1)(x−5)=(x+3)(x+5)3x2−12∗x−15=x2+8x+152x2−20x−30=0x=20±400−4(2)(−30)2(2)=5±210