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If a line and a parabola intersect exactly once, the line is said to be a tangent to the parabola.

Given that the line with equation

y=x+k

is a tangent to the parabola with equation

y=x2−2x+2

find the value of 504k

Hint

The equation

x2−2x+2=x+k

has exactly one solution.

Hint

So the discriminant of

x2−2x+2=x+k

must be 0.

Solution

The equation

x2−2x+2=x+k

has exactly one solution, so the discriminant of

x2−2x+2=x+kx2−3x+(2−k)=0

must be 0. Thus

9−4(2−k)=01+4k=0k=−14