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The curve

y=e2xln(x)

appears to have a minimum point close to x=14

  1. Show that the minimum point satisfies
2xe2x1=0
  1. Hence, use the Newton-Raphson method with a starting value of x0=14 to find two further approximations, x1 and x2, for the x coordinate of the turning point.

Give the value of x2, rounded to 3 significant figures.