Skip to content

Let

f(x)=(x−a)2(x−b),a≠b
  1. Prove that x=a is both a root and a stationary point of the cubic curve y=f(x).

  2. Prove that x=a gives a minimum of f(x) if a>b, and a maximum point if a<b. Sketch the curve in both cases.

(This finally explains why a repeated root of a cubic just touches the x axis, something that we had only assumed until now.)


Expand and differentiate. Demonstrate that x=a is a root of both f(x) and f′(x).


For (b), you should find that

f″(a)=2(a−b)

In order to sketch the cubics, notice that the coefficient of x3 in f(x) is 1, which is positive, so this is an up-down-up cubic.

You can slide a and b around in this picture to help: