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Let f(x)=ax2+bx+c and consider the curve

y=f(x)
  1. By completing the square on f(x), find the coordinates of the vertex.

  2. Find the coordinates of the vertex using differentiation (isn't that easier!)

  3. Use the second derivative test to prove that the parabola is ∪ shaped when a>0 and ∩ shaped when a<0.


For (a), you need to remove the a from the first two terms:

a[x2+bax]+c

Now you're ready to complete the square.


For (b), note that c is a constant so differentiates to 0.