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Use the picture below to explain why

sin2⁡(θ)+cos2⁡(θ)=1

Hence, solve the equations

  1. 3sin2⁡(θ)+cos2⁡(θ)=2
  2. 2cos2⁡(θ)−3sin2⁡(θ)=1

giving all solutions θ satisfying 0≤θ≤360.


By definition,

sin⁡(θ)=oppositehypotenuse=y1=y

so y=sin⁡(θ). Do similar for cos⁡(θ) and then use Pythagoras.


Since sin2⁡(θ)+cos2⁡(θ)=1, we can say that cos2⁡(θ)=1−sin2⁡(θ).

So substitute cos2⁡(θ)=1−sin2⁡(θ) into the equation, and now you only have sin in your equation, which will allow you to solve it!