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The roots of the equation

1x2+3x=1

are α and β.

Find the value of

α2+β2
Hint

Multiply both sides of the equation by x2 to begin with.

Solution1x2+3x=11+3x=x2x2−3x−1=0(x−32)2−94−1=0(x−32)2=134x=32±134=3±132