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  1. Show that

    cos2θ=12sin2θ

    and hence prove that

    sin(π8)=1222
  2. Show that

    cos2θ=2cos2θ1

    and hence find the exact value of

    cos(π12)

For (a), we have

cos2θ=cos2θsin2θ

and also

sin2θ+cos2θ=1

Substitute θ=π8 into the identity

cos2θ=12sin2θ

and remember that cos(π4)=22.