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  1. Show that

    cos⁡2θ=1−2sin2⁡θ

    and hence prove that

    sin⁡(π8)=122−2
  2. Show that

    cos⁡2θ=2cos2⁡θ−1

    and hence find the exact value of

    cos⁡(π12)

For (a), we have

cos⁡2θ=cos2⁡θ−sin2⁡θ

and also

sin2⁡θ+cos2⁡θ=1

Substitute θ=π8 into the identity

cos⁡2θ=1−2sin2⁡θ

and remember that cos⁡(π4)=22.