Solve the equations, for all $\theta$ in the domain $0^{\circ }\le \theta \le {360}^{\circ }$

1. $${\sin }^2(\theta )=\frac{1}{4}$$
2. $$3{\sin }^2(\theta )-\sqrt{3}\sin (\theta )=0$$

For (a), square root both sides - but don't forget the negative square root

For (b), you cannot divide by $\sin (\theta )$ because it might be $0.$ Instead, factor out $\sin (\theta )$.