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The double angle formulae allow us to calculate

sin⁡(2A)=2sin⁡(A)cos⁡(A)cos⁡(2A)=cos2⁡(A)−sin2⁡(A)tan⁡(2A)=2tan⁡(A)1−tan2⁡(A)

This is really just an application of the addition formulae that we've already learned, as we'll see in the first example.

A brief note about cos⁡(2A). Because sin2⁡A+cos2⁡A=1, we can get alternative forms of the double angle formula for cos as so

cos⁡(2A)=cos2⁡(A)−sin2⁡(A)=2cos2⁡(A)−1=1−2sin2⁡(A)

These can be supremely useful (as will be explained in the first example).


  1. Given that cos⁡x=12 for acute x, find the value of sin⁡(2x).

  2. Given that cos⁡θ=0.9 find the value of cos⁡2θ.