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Use the formula

tan(A±B)=tanA±tanB1tanAtanB

to find the values of:

  1. tan(π12)
  2. tan(5π12)
  3. tan(165)

For (a),

π12=π3π4

For (b),

5π12=π4+π6

or you could do

5π12=π3+π12

and make use of the answer to part (a).


For (c), notice that

165=18015

In part (a), we found tan(π12), and π12 rad is 15.