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Use the formula

tan⁡(A±B)=tan⁡A±tan⁡B1∓tan⁡Atan⁡B

to find the values of:

  1. tan⁡(π12)
  2. tan⁡(5π12)
  3. tan⁡(165∘)

For (a),

π12=π3−π4

For (b),

5π12=π4+π6

or you could do

5π12=π3+π12

and make use of the answer to part (a).


For (c), notice that

165=180−15

In part (a), we found tan⁡(π12), and π12 rad is 15∘.