Skip to content

By considering a Riemann sum with n rectangles of equal width:

  1. Show that

    ∫0bxdx≈b2n2∑k=1n(k−1)
  2. Hence, show that

    ∫0bxdx≈b22(1−1n)
  3. Hence, show that

    ∫0bxdx=b22
  4. By sketching

    y=x,0≤x≤b

    explain why the result in part (c) is to be expected.