Skip to content

By considering a Riemann sum with n rectangles of equal width:

  1. Show that

    0bxdxb2n2k=1n(k1)
  2. Hence, show that

    0bxdxb22(11n)
  3. Hence, show that

    0bxdx=b22
  4. By sketching

    y=x,0xb

    explain why the result in part (c) is to be expected.