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The tangent to the curve

y=2x3−3x2−12x

at the point P passes through the maximum point of the curve.

Find the coordinates of P.


Let P have x coordinate of p. Find the tangent to the curve at the point

(p,2p3−3p2−12p)

You know that (−1,7) lies on the tangent, so you have a point to substitute into the equation of the tangent.

You should now have an equation in terms of p only. It looks nasty, but it turns into an ok cubic.


The solutions, p, to the cubic you found in hint 2