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Expanding something like

(a+b)5

would be possible, but boring. Consider

(a+b)(a+b)(a+b)(a+b)(a+b)

Terms of the form, for example,

a3b2

are obtained by choosing a b from 2 of the brackets (and thus an a from the remaining 3 brackets). So a3b2 would turn up

5C3=(53)

times.

General formula ​

Generally, we have

(a+b)n=(n0)an+(n1)an−1b+(n2)an−2b2+…+(nn−1)abn−1+(nn)bn

This formula looks pretty scary, but it makes a lot more sense once you've seen some examples.


  1. Use the binomial expansion formula to expand

    (a+b)5
  2. Use the binomial expansion formula to expand

    (2+3x)4
  3. Expand and simplify

    (1p−p)5