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Functions of the form 1sinx occur so frequently that we give them their own names:

1cosx=secx1sinx=\cosecx1tanx=cotx

Starting with the identity sin2x+cos2x=1, we can show that

tan2x+1=sec2x

and

1+cot2x=\cosec2x
  1. Sketch the curve

    y=\cosecx,2πx2π
  2. Show that

    1+cot2x=\cosec2x
  3. Solve the equation

    4cot2θ+7=8\cosecθ

    giving all θ satisfying 0θ2π